Page 96 - JavaScript

let odd = numbers.filter(n => n % 2 !== 0); // can be shortened to (n => n % 2)

odd would contain the following array: [5, 43].

It also works on an array of objects:

var people = [{
id: 1,
name: "John",
age: 28
}, {
id: 2,
name: "Jane",
age: 31
}, {
id: 3,
name: "Peter",
age: 55
}];

5.1

var young = people.filter(function(person) {
return person.age < 35;
});

6

let young = people.filter(person => person.age < 35);

young would contain the following array:

[{
id: 1,
name: "John",
age: 28
}, {
id: 2,
name: "Jane",
age: 31
}]

You can search in the whole array for a value like this:

var young = people.filter((obj) => {
var flag = false;
Object.values(obj).forEach((val) => {
if(String(val).indexOf("J") > -1) {
flag = true;
return;
}
});
if(flag) return obj;
});

https://riptutorial.com/ 53